2017•arXiv (Cornell University)Open access

Reflexivity of functors of modules

Adrián Gordillo-Merino, José Navarro, Pedro Sancho

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Abstract

Let $R$ be an associative ring with unit. %It is natural to We consider $R$-modules as module functors in the following way: if $M$ is a (left) $R$-module, let $\mathcal M$ be the functor of $\mathcal R$-modules defined by $\mathcal M(S) := S\otimes_R M$ for every $R$-algebra $S$. With the corresponding notion of dual functor, we prove that the natural morphism of functors $\mathcal M\to \mathcal M^{**}$ is an isomorphism.

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What this paper is about

Let $R$ be an associative ring with unit. %It is natural to We consider $R$-modules as module functors in the following way: if $M$ is a (left) $R$-module, let $\mathcal M$ be the functor of $\mathcal R$-modules defined by $\mathcal M(S) := S\otimes_R M$ for every $R$-algebra $S$. With the corresponding notion of dual functor, we prove that the natural morphism of functors $\mathcal M\to \mathcal M^{**}$ is an isomorphism.

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Available abstract

Let $R$ be an associative ring with unit. %It is natural to We consider $R$-modules as module functors in the following way: if $M$ is a (left) $R$-module, let $\mathcal M$ be the functor of $\mathcal R$-modules defined by $\mathcal M(S) := S\otimes_R M$ for every $R$-algebra $S$. With the corresponding notion of dual functor, we prove that the natural morphism of functors $\mathcal M\to \mathcal M^{**}$ is an isomorphism.

Key concepts: Functor, Natural transformation, Morphism, Mathematics, Isomorphism (crystallography), Pure mathematics, Unit (ring theory), Derived functor

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