2000•Proceedings of the Japan Academy Series A Mathematical SciencesOpen access

On the Diophantine equation $x(x + 1) \dotsm (x + n) + 1 = y^2$

Nobuhisa Abe

Open full text 1 citations

Abstract

Let $\mathbf{N}$ denote the set of natural numbers $\{1, 2, 3, \ldots\}$. $n$ being an odd natural number, we consider the Diophantine equation as mentioned in the title and solve it completely for $n \leq 15$, i.e. find all $(x,y) \in \mathbf{N}^2$ satisfying this equation.

Open-access reader

About this research paper

What this paper is about

Let $\mathbf{N}$ denote the set of natural numbers $\{1, 2, 3, \ldots\}$. $n$ being an odd natural number, we consider the Diophantine equation as mentioned in the title and solve it completely for $n \leq 15$, i.e. find all $(x,y) \in \mathbf{N}^2$ satisfying this equation.

Why it matters

OpenAlex reports 1 citations for this work. Citation counts describe recorded attention and do not establish research quality.

Key contribution

A contribution statement is not available in the OpenAlex record.

Method / approach

Method details are not available in the OpenAlex metadata.

Main findings

Findings are not separately available in the OpenAlex metadata.

Limitations

Limitations are not available in the OpenAlex metadata.

Applications

Application details are not available in the OpenAlex metadata.

Available abstract

Let $\mathbf{N}$ denote the set of natural numbers $\{1, 2, 3, \ldots\}$. $n$ being an odd natural number, we consider the Diophantine equation as mentioned in the title and solve it completely for $n \leq 15$, i.e. find all $(x,y) \in \mathbf{N}^2$ satisfying this equation.

Key concepts: Diophantine equation, Natural number, Mathematics, Combinatorics, Discrete mathematics

Related papers

Back to paper searchBrowse research topicsOriginal source
On the Diophantine equation $x(x + 1) \dotsm (x + n) + 1 = y^2$ — Research Paper | ScholarLens