1989•eCommons (Cornell University)Requires access

An Example of a Theorem that has Contradictory Relativizations and a Diagonalization Proof

Richard Chang

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Abstract

We construct a computable space bound $S(n)$, with $n^{2} less than S(n) less than n^{3}$ and show by diagonalization that DSPACE [$S(n)$] = DSPACE [$S(n)$ log $n$]. Moreover, we can show that there exists an oracle $A$ such that DSPACE [$S(n)$] $\neq$ DSPACE$^{A}$[$S(n)$ log $n$]. This is a counterexample to the belief that is a theorem has contradictory relativizations, then is cannot be proved using standard techniques like diagonalization [7].

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What this paper is about

We construct a computable space bound $S(n)$, with $n^{2} less than S(n) less than n^{3}$ and show by diagonalization that DSPACE [$S(n)$] = DSPACE [$S(n)$ log $n$]. Moreover, we can show that there exists an oracle $A$ such that DSPACE [$S(n)$] $\neq$ DSPACE$^{A}$[$S(n)$ log $n$]. This is a counterexample to the belief that is a theorem has contradictory relativizations, then is cannot be proved using standard techniques like diagonalization [7].

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Available abstract

We construct a computable space bound $S(n)$, with $n^{2} less than S(n) less than n^{3}$ and show by diagonalization that DSPACE [$S(n)$] = DSPACE [$S(n)$ log $n$]. Moreover, we can show that there exists an oracle $A$ such that DSPACE [$S(n)$] $\neq$ DSPACE$^{A}$[$S(n)$ log $n$]. This is a counterexample to the belief that is a theorem has contradictory relativizations, then is cannot be proved using standard techniques like diagonalization [7].

Key concepts: DSPACE, Oracle, Counterexample, NSPACE, Mathematics, Construct (python library), Space (punctuation), PSPACE

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